122=-a+3(1+6a)

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Solution for 122=-a+3(1+6a) equation: 



122=-a+3(1+6a)

We move all terms to the left:

122-(-a+3(1+6a))=0

We add all the numbers together, and all the variables

-(-a+3(6a+1))+122=0



We calculate terms in parentheses: -(-a+3(6a+1)), so:

-a+3(6a+1)

We add all the numbers together, and all the variables

-1a+3(6a+1)

We multiply parentheses

-1a+18a+3

We add all the numbers together, and all the variables

17a+3

Back to the equation:

-(17a+3)



We get rid of parentheses

-17a-3+122=0

We add all the numbers together, and all the variables

-17a+119=0

We move all terms containing a to the left, all other terms to the right

-17a=-119

a=-119/-17

a=+7

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