17x-5(3x-11)=41

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Solution for 17x-5(3x-11)=41 equation: 



17x-5(3x-11)=41

We move all terms to the left:

17x-5(3x-11)-(41)=0

We multiply parentheses

17x-15x+55-41=0

We add all the numbers together, and all the variables

2x+14=0

We move all terms containing x to the left, all other terms to the right

2x=-14

x=-14/2

x=-7

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