122+(8x+20)=(22x-3)

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Solution for 122+(8x+20)=(22x-3) equation: 



122+(8x+20)=(22x-3)

We move all terms to the left:

122+(8x+20)-((22x-3))=0

We get rid of parentheses

8x-((22x-3))+20+122=0



We calculate terms in parentheses: -((22x-3)), so:

(22x-3)

We get rid of parentheses

22x-3

Back to the equation:

-(22x-3)



We add all the numbers together, and all the variables

8x-(22x-3)+142=0

We get rid of parentheses

8x-22x+3+142=0

We add all the numbers together, and all the variables

-14x+145=0

We move all terms containing x to the left, all other terms to the right

-14x=-145

x=-145/-14

x=10+5/14

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