5(3x-8)-4=5(x-3)+11

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Solution for 5(3x-8)-4=5(x-3)+11 equation: 



5(3x-8)-4=5(x-3)+11

We move all terms to the left:

5(3x-8)-4-(5(x-3)+11)=0

We multiply parentheses

15x-(5(x-3)+11)-40-4=0



We calculate terms in parentheses: -(5(x-3)+11), so:

5(x-3)+11

We multiply parentheses

5x-15+11

We add all the numbers together, and all the variables

5x-4

Back to the equation:

-(5x-4)



We add all the numbers together, and all the variables

15x-(5x-4)-44=0

We get rid of parentheses

15x-5x+4-44=0

We add all the numbers together, and all the variables

10x-40=0

We move all terms containing x to the left, all other terms to the right

10x=40

x=40/10

x=4

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