120=1/2(3x+2)(x+2)

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Solution for 120=1/2(3x+2)(x+2) equation: 



120=1/2(3x+2)(x+2)

We move all terms to the left:

120-(1/2(3x+2)(x+2))=0



Domain of the equation: 2(3x+2)(x+2))!=0

x∈R



We multiply parentheses ..

-(1/2(+3x^2+6x+2x+4))+120=0

We multiply all the terms by the denominator


-(1+120*2(+3x^2+6x+2x+4))=0



We calculate terms in parentheses: -(1+120*2(+3x^2+6x+2x+4)), so:

1+120*2(+3x^2+6x+2x+4)

determiningTheFunctionDomain
120*2(+3x^2+6x+2x+4)+1

Wy multiply elements

240x(++1

We use the square of the difference formula

240x(+1

Back to the equation:

-(240x(+1)



We add all the numbers together, and all the variables

-(240x1=0

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