120=(180(n-2))/n

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Solution for 120=(180(n-2))/n equation: 



120=(180(n-2))/n

We move all terms to the left:

120-((180(n-2))/n)=0



Domain of the equation: n)!=0

n!=0/1

n!=0

n∈R



We multiply all the terms by the denominator


-((180(n-2))+120*n)=0



We calculate terms in parentheses: -((180(n-2))+120*n), so:

(180(n-2))+120*n

We add all the numbers together, and all the variables

120n+(180(n-2))



We calculate terms in parentheses: +(180(n-2)), so:

180(n-2)

We multiply parentheses

180n-360

Back to the equation:

+(180n-360)



We get rid of parentheses

120n+180n-360

We add all the numbers together, and all the variables

300n-360

Back to the equation:

-(300n-360)



We get rid of parentheses

-300n+360=0

We move all terms containing n to the left, all other terms to the right

-300n=-360

n=-360/-300

n=1+1/5

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