2x/3x+7=1x/2x-3

Solution for 2x/3x+7=1x/2x-3 equation:

2x/3x+7=1x/2x-3

We move all terms to the left:

2x/3x+7-(1x/2x-3)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 2x-3)!=0

x∈R


We get rid of parentheses

2x/3x-1x/2x+3+7=0

We calculate fractions


(-3x^2)/6x^2+4x^2/6x^2+3+7=0

We add all the numbers together, and all the variables

(-3x^2)/6x^2+4x^2/6x^2+10=0

We multiply all the terms by the denominator


(-3x^2)+4x^2+10*6x^2=0

We add all the numbers together, and all the variables

4x^2+(-3x^2)+10*6x^2=0

Wy multiply elements

4x^2+(-3x^2)+60x^2=0

We get rid of parentheses

4x^2-3x^2+60x^2=0

We add all the numbers together, and all the variables

61x^2=0

a = 61; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·61·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{122}=0$