1200=x(10*x)

Solution for 1200=x(10*x) equation:

1200=x(10*x)

We move all terms to the left:

1200-(x(10*x))=0

We add all the numbers together, and all the variables

-(x(+10x))+1200=0


We calculate terms in parentheses: -(x(+10x)), so:

x(+10x)

We multiply parentheses

10x^2

Back to the equation:

-(10x^2)


a = -10; b = 0; c = +1200;
Δ = b2-4ac
Δ = 02-4·(-10)·1200
Δ = 48000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{48000}=\sqrt{1600*30}=\sqrt{1600}*\sqrt{30}=40\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{30}}{2*-10}=\frac{0-40\sqrt{30}}{-20}
=-\frac{40\sqrt{30}}{-20}
=-\frac{2\sqrt{30}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{30}}{2*-10}=\frac{0+40\sqrt{30}}{-20}
=\frac{40\sqrt{30}}{-20}
=\frac{2\sqrt{30}}{-1}
$