3x2-8=100

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Solution for 3x2-8=100 equation:



3x^2-8=100
We move all terms to the left:
3x^2-8-(100)=0
We add all the numbers together, and all the variables
3x^2-108=0
a = 3; b = 0; c = -108;
Δ = b2-4ac
Δ = 02-4·3·(-108)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36}{2*3}=\frac{-36}{6} =-6 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36}{2*3}=\frac{36}{6} =6 $

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