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120+4/3x=2x
We move all terms to the left:
120+4/3x-(2x)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
-2x+4/3x+120=0
We multiply all the terms by the denominator
-2x*3x+120*3x+4=0
Wy multiply elements
-6x^2+360x+4=0
a = -6; b = 360; c = +4;
Δ = b2-4ac
Δ = 3602-4·(-6)·4
Δ = 129696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{129696}=\sqrt{16*8106}=\sqrt{16}*\sqrt{8106}=4\sqrt{8106}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(360)-4\sqrt{8106}}{2*-6}=\frac{-360-4\sqrt{8106}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(360)+4\sqrt{8106}}{2*-6}=\frac{-360+4\sqrt{8106}}{-12} $
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