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(5x-12)=(52+2x)
We move all terms to the left:
(5x-12)-((52+2x))=0
We add all the numbers together, and all the variables
(5x-12)-((2x+52))=0
We get rid of parentheses
5x-((2x+52))-12=0
We calculate terms in parentheses: -((2x+52)), so:We get rid of parentheses
(2x+52)
We get rid of parentheses
2x+52
Back to the equation:
-(2x+52)
5x-2x-52-12=0
We add all the numbers together, and all the variables
3x-64=0
We move all terms containing x to the left, all other terms to the right
3x=64
x=64/3
x=21+1/3
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