-5(w+2)=w-2+2(4w+2)

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Solution for -5(w+2)=w-2+2(4w+2) equation: 



-5(w+2)=w-2+2(4w+2)

We move all terms to the left:

-5(w+2)-(w-2+2(4w+2))=0

We multiply parentheses

-5w-(w-2+2(4w+2))-10=0



We calculate terms in parentheses: -(w-2+2(4w+2)), so:

w-2+2(4w+2)

determiningTheFunctionDomain
w+2(4w+2)-2

We multiply parentheses

w+8w+4-2

We add all the numbers together, and all the variables

9w+2

Back to the equation:

-(9w+2)



We get rid of parentheses

-5w-9w-2-10=0

We add all the numbers together, and all the variables

-14w-12=0

We move all terms containing w to the left, all other terms to the right

-14w=12

w=12/-14

w=-6/7

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