6(x+1)/8=3(x+2)/7

Solution for 6(x+1)/8=3(x+2)/7 equation:

6(x+1)/8=3(x+2)/7

We move all terms to the left:

6(x+1)/8-(3(x+2)/7)=0

We calculate fractions


6x/()+(-(3(x+2)*8)/()=0


We calculate terms in parentheses: +(-(3(x+2)*8)/(), so:

-(3(x+2)*8)/(

We multiply all the terms by the denominator


-(3(x+2)*8)


We calculate terms in parentheses: -(3(x+2)*8), so:

3(x+2)*8

We multiply parentheses

24x+48

Back to the equation:

-(24x+48)


We get rid of parentheses

-24x-48

Back to the equation:

+(-24x-48)


We get rid of parentheses

6x/()-24x-48=0

We multiply all the terms by the denominator


6x-24x*()-48*()=0

We add all the numbers together, and all the variables

6x-24x*()=0