120+20b=2/3(280+20b)

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Solution for 120+20b=2/3(280+20b) equation: 



120+20b=2/3(280+20b)

We move all terms to the left:

120+20b-(2/3(280+20b))=0



Domain of the equation: 3(280+20b))!=0

b∈R



We add all the numbers together, and all the variables

20b-(2/3(20b+280))+120=0

We multiply all the terms by the denominator


20b*3(20b+280))-(2+120*3(20b+280))=0

Wy multiply elements

60b^2(2+360b(2=0

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