5(z-1)=2(3-2z)+17

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Solution for 5(z-1)=2(3-2z)+17 equation: 



5(z-1)=2(3-2z)+17

We move all terms to the left:

5(z-1)-(2(3-2z)+17)=0

We add all the numbers together, and all the variables

5(z-1)-(2(-2z+3)+17)=0

We multiply parentheses

5z-(2(-2z+3)+17)-5=0



We calculate terms in parentheses: -(2(-2z+3)+17), so:

2(-2z+3)+17

We multiply parentheses

-4z+6+17

We add all the numbers together, and all the variables

-4z+23

Back to the equation:

-(-4z+23)



We get rid of parentheses

5z+4z-23-5=0

We add all the numbers together, and all the variables

9z-28=0

We move all terms containing z to the left, all other terms to the right

9z=28

z=28/9

z=3+1/9

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