12/3(j)=15

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Solution for 12/3(j)=15 equation: 



12/3(j)=15

We move all terms to the left:

12/3(j)-(15)=0



Domain of the equation: 3j!=0

j!=0/3

j!=0

j∈R



We multiply all the terms by the denominator


-15*3j+12=0

Wy multiply elements

-45j+12=0

We move all terms containing j to the left, all other terms to the right

-45j=-12

j=-12/-45

j=4/15

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