-5y+2(4y+5)=7-7(2-y)

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Solution for -5y+2(4y+5)=7-7(2-y) equation:



-5y+2(4y+5)=7-7(2-y)
We move all terms to the left:
-5y+2(4y+5)-(7-7(2-y))=0
We add all the numbers together, and all the variables
-5y+2(4y+5)-(7-7(-1y+2))=0
We multiply parentheses
-5y+8y-(7-7(-1y+2))+10=0
We calculate terms in parentheses: -(7-7(-1y+2)), so:
7-7(-1y+2)
determiningTheFunctionDomain -7(-1y+2)+7
We multiply parentheses
7y-14+7
We add all the numbers together, and all the variables
7y-7
Back to the equation:
-(7y-7)
We add all the numbers together, and all the variables
3y-(7y-7)+10=0
We get rid of parentheses
3y-7y+7+10=0
We add all the numbers together, and all the variables
-4y+17=0
We move all terms containing y to the left, all other terms to the right
-4y=-17
y=-17/-4
y=4+1/4

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