12-5(6+x)-x=x+5(2x-4)-7

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Solution for 12-5(6+x)-x=x+5(2x-4)-7 equation:



12-5(6+x)-x=x+5(2x-4)-7
We move all terms to the left:
12-5(6+x)-x-(x+5(2x-4)-7)=0
We add all the numbers together, and all the variables
-5(x+6)-x-(x+5(2x-4)-7)+12=0
We add all the numbers together, and all the variables
-1x-5(x+6)-(x+5(2x-4)-7)+12=0
We multiply parentheses
-1x-5x-(x+5(2x-4)-7)-30+12=0
We calculate terms in parentheses: -(x+5(2x-4)-7), so:
x+5(2x-4)-7
We multiply parentheses
x+10x-20-7
We add all the numbers together, and all the variables
11x-27
Back to the equation:
-(11x-27)
We add all the numbers together, and all the variables
-6x-(11x-27)-18=0
We get rid of parentheses
-6x-11x+27-18=0
We add all the numbers together, and all the variables
-17x+9=0
We move all terms containing x to the left, all other terms to the right
-17x=-9
x=-9/-17
x=9/17

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