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(2x-20)+(3x+5)+x=180
We move all terms to the left:
(2x-20)+(3x+5)+x-(180)=0
We add all the numbers together, and all the variables
x+(2x-20)+(3x+5)-180=0
We get rid of parentheses
x+2x+3x-20+5-180=0
We add all the numbers together, and all the variables
6x-195=0
We move all terms containing x to the left, all other terms to the right
6x=195
x=195/6
x=32+1/2
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