12-2/3m+4-3/4m=0

Solution for 12-2/3m+4-3/4m=0 equation:

12-2/3m+4-3/4m=0


Domain of the equation: 3m!=0

m!=0/3

m!=0

m∈R



Domain of the equation: 4m!=0

m!=0/4

m!=0

m∈R


We add all the numbers together, and all the variables

-2/3m-3/4m+16=0

We calculate fractions


(-8m)/12m^2+(-9m)/12m^2+16=0

We multiply all the terms by the denominator


(-8m)+(-9m)+16*12m^2=0

Wy multiply elements

192m^2+(-8m)+(-9m)=0

We get rid of parentheses

192m^2-8m-9m=0

We add all the numbers together, and all the variables

192m^2-17m=0

a = 192; b = -17; c = 0;
Δ = b2-4ac
Δ = -172-4·192·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-17}{2*192}=\frac{0}{384}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+17}{2*192}=\frac{34}{384}
=17/192
$