12-2(5-3x)=6(-4x+3)-10x

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Solution for 12-2(5-3x)=6(-4x+3)-10x equation:



12-2(5-3x)=6(-4x+3)-10x
We move all terms to the left:
12-2(5-3x)-(6(-4x+3)-10x)=0
We add all the numbers together, and all the variables
-2(-3x+5)-(6(-4x+3)-10x)+12=0
We multiply parentheses
6x-(6(-4x+3)-10x)-10+12=0
We calculate terms in parentheses: -(6(-4x+3)-10x), so:
6(-4x+3)-10x
We add all the numbers together, and all the variables
-10x+6(-4x+3)
We multiply parentheses
-10x-24x+18
We add all the numbers together, and all the variables
-34x+18
Back to the equation:
-(-34x+18)
We add all the numbers together, and all the variables
6x-(-34x+18)+2=0
We get rid of parentheses
6x+34x-18+2=0
We add all the numbers together, and all the variables
40x-16=0
We move all terms containing x to the left, all other terms to the right
40x=16
x=16/40
x=2/5

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