-12-2(5-3x)=6(4x+3)-10x

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Solution for -12-2(5-3x)=6(4x+3)-10x equation: 



-12-2(5-3x)=6(4x+3)-10x

We move all terms to the left:

-12-2(5-3x)-(6(4x+3)-10x)=0

We add all the numbers together, and all the variables

-2(-3x+5)-(6(4x+3)-10x)-12=0

We multiply parentheses

6x-(6(4x+3)-10x)-10-12=0



We calculate terms in parentheses: -(6(4x+3)-10x), so:

6(4x+3)-10x

We add all the numbers together, and all the variables

-10x+6(4x+3)

We multiply parentheses

-10x+24x+18

We add all the numbers together, and all the variables

14x+18

Back to the equation:

-(14x+18)



We add all the numbers together, and all the variables

6x-(14x+18)-22=0

We get rid of parentheses

6x-14x-18-22=0

We add all the numbers together, and all the variables

-8x-40=0

We move all terms containing x to the left, all other terms to the right

-8x=40

x=40/-8

x=-5

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