12-(3r+2)=-7(r+6)

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Solution for 12-(3r+2)=-7(r+6) equation: 



12-(3r+2)=-7(r+6)

We move all terms to the left:

12-(3r+2)-(-7(r+6))=0

We get rid of parentheses

-3r-(-7(r+6))-2+12=0



We calculate terms in parentheses: -(-7(r+6)), so:

-7(r+6)

We multiply parentheses

-7r-42

Back to the equation:

-(-7r-42)



We add all the numbers together, and all the variables

-3r-(-7r-42)+10=0

We get rid of parentheses

-3r+7r+42+10=0

We add all the numbers together, and all the variables

4r+52=0

We move all terms containing r to the left, all other terms to the right

4r=-52

r=-52/4

r=-13

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