9-1/5(2n-6)=n+2

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Solution for 9-1/5(2n-6)=n+2 equation: 



9-1/5(2n-6)=n+2

We move all terms to the left:

9-1/5(2n-6)-(n+2)=0



Domain of the equation: 5(2n-6)!=0

n∈R



We get rid of parentheses

-1/5(2n-6)-n-2+9=0

We multiply all the terms by the denominator


-n*5(2n-6)-2*5(2n-6)+9*5(2n-6)-1=0

Wy multiply elements

-5n^2(2-10n(2+45n(2-1=0

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