12+5(9+y)=6(11-y)

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Solution for 12+5(9+y)=6(11-y) equation: 



12+5(9+y)=6(11-y)

We move all terms to the left:

12+5(9+y)-(6(11-y))=0

We add all the numbers together, and all the variables

5(y+9)-(6(-1y+11))+12=0

We multiply parentheses

5y-(6(-1y+11))+45+12=0



We calculate terms in parentheses: -(6(-1y+11)), so:

6(-1y+11)

We multiply parentheses

-6y+66

Back to the equation:

-(-6y+66)



We add all the numbers together, and all the variables

5y-(-6y+66)+57=0

We get rid of parentheses

5y+6y-66+57=0

We add all the numbers together, and all the variables

11y-9=0

We move all terms containing y to the left, all other terms to the right

11y=9

y=9/11

y=9/11

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