7(3+x)=3(7-x)+30

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Solution for 7(3+x)=3(7-x)+30 equation: 



7(3+x)=3(7-x)+30

We move all terms to the left:

7(3+x)-(3(7-x)+30)=0

We add all the numbers together, and all the variables

7(x+3)-(3(-1x+7)+30)=0

We multiply parentheses

7x-(3(-1x+7)+30)+21=0



We calculate terms in parentheses: -(3(-1x+7)+30), so:

3(-1x+7)+30

We multiply parentheses

-3x+21+30

We add all the numbers together, and all the variables

-3x+51

Back to the equation:

-(-3x+51)



We get rid of parentheses

7x+3x-51+21=0

We add all the numbers together, and all the variables

10x-30=0

We move all terms containing x to the left, all other terms to the right

10x=30

x=30/10

x=3

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