12(x-5)+3x=2+(x-8)

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Solution for 12(x-5)+3x=2+(x-8) equation: 



12(x-5)+3x=2+(x-8)

We move all terms to the left:

12(x-5)+3x-(2+(x-8))=0

We add all the numbers together, and all the variables

3x+12(x-5)-(2+(x-8))=0

We multiply parentheses

3x+12x-(2+(x-8))-60=0



We calculate terms in parentheses: -(2+(x-8)), so:

2+(x-8)

determiningTheFunctionDomain
(x-8)+2

We get rid of parentheses

x-8+2

We add all the numbers together, and all the variables

x-6

Back to the equation:

-(x-6)



We add all the numbers together, and all the variables

15x-(x-6)-60=0

We get rid of parentheses

15x-x+6-60=0

We add all the numbers together, and all the variables

14x-54=0

We move all terms containing x to the left, all other terms to the right

14x=54

x=54/14

x=3+6/7

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