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(5y-6)=(4y+12)
We move all terms to the left:
(5y-6)-((4y+12))=0
We get rid of parentheses
5y-((4y+12))-6=0
We calculate terms in parentheses: -((4y+12)), so:We get rid of parentheses
(4y+12)
We get rid of parentheses
4y+12
Back to the equation:
-(4y+12)
5y-4y-12-6=0
We add all the numbers together, and all the variables
y-18=0
We move all terms containing y to the left, all other terms to the right
y=18
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