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12(x-3)=3(2x-4)
We move all terms to the left:
12(x-3)-(3(2x-4))=0
We multiply parentheses
12x-(3(2x-4))-36=0
We calculate terms in parentheses: -(3(2x-4)), so:We get rid of parentheses
3(2x-4)
We multiply parentheses
6x-12
Back to the equation:
-(6x-12)
12x-6x+12-36=0
We add all the numbers together, and all the variables
6x-24=0
We move all terms containing x to the left, all other terms to the right
6x=24
x=24/6
x=4
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