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3x(x+20)44=x
We move all terms to the left:
3x(x+20)44-(x)=0
We add all the numbers together, and all the variables
-1x+3x(x+20)44=0
We multiply parentheses
132x^2-1x+2640x=0
We add all the numbers together, and all the variables
132x^2+2639x=0
a = 132; b = 2639; c = 0;
Δ = b2-4ac
Δ = 26392-4·132·0
Δ = 6964321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6964321}=2639$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2639)-2639}{2*132}=\frac{-5278}{264} =-19+131/132 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2639)+2639}{2*132}=\frac{0}{264} =0 $
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