12(x-3)+2x=4(x-2)

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Solution for 12(x-3)+2x=4(x-2) equation: 



12(x-3)+2x=4(x-2)

We move all terms to the left:

12(x-3)+2x-(4(x-2))=0

We add all the numbers together, and all the variables

2x+12(x-3)-(4(x-2))=0

We multiply parentheses

2x+12x-(4(x-2))-36=0



We calculate terms in parentheses: -(4(x-2)), so:

4(x-2)

We multiply parentheses

4x-8

Back to the equation:

-(4x-8)



We add all the numbers together, and all the variables

14x-(4x-8)-36=0

We get rid of parentheses

14x-4x+8-36=0

We add all the numbers together, and all the variables

10x-28=0

We move all terms containing x to the left, all other terms to the right

10x=28

x=28/10

x=2+4/5

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