2(d-5)=3(d+4)

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Solution for 2(d-5)=3(d+4) equation: 



2(d-5)=3(d+4)

We move all terms to the left:

2(d-5)-(3(d+4))=0

We multiply parentheses

2d-(3(d+4))-10=0



We calculate terms in parentheses: -(3(d+4)), so:

3(d+4)

We multiply parentheses

3d+12

Back to the equation:

-(3d+12)



We get rid of parentheses

2d-3d-12-10=0

We add all the numbers together, and all the variables

-1d-22=0

We move all terms containing d to the left, all other terms to the right

-d=22

d=22/-1

d=-22

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