12(x-3)+18=4(2x-3)

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Solution for 12(x-3)+18=4(2x-3) equation: 



12(x-3)+18=4(2x-3)

We move all terms to the left:

12(x-3)+18-(4(2x-3))=0

We multiply parentheses

12x-(4(2x-3))-36+18=0



We calculate terms in parentheses: -(4(2x-3)), so:

4(2x-3)

We multiply parentheses

8x-12

Back to the equation:

-(8x-12)



We add all the numbers together, and all the variables

12x-(8x-12)-18=0

We get rid of parentheses

12x-8x+12-18=0

We add all the numbers together, and all the variables

4x-6=0

We move all terms containing x to the left, all other terms to the right

4x=6

x=6/4

x=1+1/2

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