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3(x-5)-5(x-3)=x+2-(x-8)
We move all terms to the left:
3(x-5)-5(x-3)-(x+2-(x-8))=0
We multiply parentheses
3x-5x-(x+2-(x-8))-15+15=0
We calculate terms in parentheses: -(x+2-(x-8)), so:We add all the numbers together, and all the variables
x+2-(x-8)
determiningTheFunctionDomain x-(x-8)+2
We get rid of parentheses
x-x+8+2
We add all the numbers together, and all the variables
10
Back to the equation:
-(10)
-2x-10=0
We move all terms containing x to the left, all other terms to the right
-2x=10
x=10/-2
x=-5
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