12(x-2)+3x=13(x+12)=10x

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Solution for 12(x-2)+3x=13(x+12)=10x equation:



12(x-2)+3x=13(x+12)=10x
We move all terms to the left:
12(x-2)+3x-(13(x+12))=0
We add all the numbers together, and all the variables
3x+12(x-2)-(13(x+12))=0
We multiply parentheses
3x+12x-(13(x+12))-24=0
We calculate terms in parentheses: -(13(x+12)), so:
13(x+12)
We multiply parentheses
13x+156
Back to the equation:
-(13x+156)
We add all the numbers together, and all the variables
15x-(13x+156)-24=0
We get rid of parentheses
15x-13x-156-24=0
We add all the numbers together, and all the variables
2x-180=0
We move all terms containing x to the left, all other terms to the right
2x=180
x=180/2
x=90

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