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3/2x=5/x-2
We move all terms to the left:
3/2x-(5/x-2)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: x-2)!=0We get rid of parentheses
x∈R
3/2x-5/x+2=0
We calculate fractions
3x/2x^2+(-10x)/2x^2+2=0
We multiply all the terms by the denominator
3x+(-10x)+2*2x^2=0
Wy multiply elements
4x^2+3x+(-10x)=0
We get rid of parentheses
4x^2+3x-10x=0
We add all the numbers together, and all the variables
4x^2-7x=0
a = 4; b = -7; c = 0;
Δ = b2-4ac
Δ = -72-4·4·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-7}{2*4}=\frac{0}{8} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+7}{2*4}=\frac{14}{8} =1+3/4 $
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