12(x-1)-(3x-8)=3(x+5)+(4x-1)

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Solution for 12(x-1)-(3x-8)=3(x+5)+(4x-1) equation: 



12(x-1)-(3x-8)=3(x+5)+(4x-1)

We move all terms to the left:

12(x-1)-(3x-8)-(3(x+5)+(4x-1))=0

We multiply parentheses

12x-(3x-8)-(3(x+5)+(4x-1))-12=0

We get rid of parentheses

12x-3x-(3(x+5)+(4x-1))+8-12=0



We calculate terms in parentheses: -(3(x+5)+(4x-1)), so:

3(x+5)+(4x-1)

We multiply parentheses

3x+(4x-1)+15

We get rid of parentheses

3x+4x-1+15

We add all the numbers together, and all the variables

7x+14

Back to the equation:

-(7x+14)



We add all the numbers together, and all the variables

9x-(7x+14)-4=0

We get rid of parentheses

9x-7x-14-4=0

We add all the numbers together, and all the variables

2x-18=0

We move all terms containing x to the left, all other terms to the right

2x=18

x=18/2

x=9

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