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2x(3x+8)-6x-16=0
We add all the numbers together, and all the variables
-6x+2x(3x+8)-16=0
We multiply parentheses
6x^2-6x+16x-16=0
We add all the numbers together, and all the variables
6x^2+10x-16=0
a = 6; b = 10; c = -16;
Δ = b2-4ac
Δ = 102-4·6·(-16)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-22}{2*6}=\frac{-32}{12} =-2+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+22}{2*6}=\frac{12}{12} =1 $
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