12(x+4)=6x+5(3x-20)

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Solution for 12(x+4)=6x+5(3x-20) equation: 



12(x+4)=6x+5(3x-20)

We move all terms to the left:

12(x+4)-(6x+5(3x-20))=0

We multiply parentheses

12x-(6x+5(3x-20))+48=0



We calculate terms in parentheses: -(6x+5(3x-20)), so:

6x+5(3x-20)

We multiply parentheses

6x+15x-100

We add all the numbers together, and all the variables

21x-100

Back to the equation:

-(21x-100)



We get rid of parentheses

12x-21x+100+48=0

We add all the numbers together, and all the variables

-9x+148=0

We move all terms containing x to the left, all other terms to the right

-9x=-148

x=-148/-9

x=16+4/9

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