2(2k-1)=2(k-2)

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Solution for 2(2k-1)=2(k-2) equation: 



2(2k-1)=2(k-2)

We move all terms to the left:

2(2k-1)-(2(k-2))=0

We multiply parentheses

4k-(2(k-2))-2=0



We calculate terms in parentheses: -(2(k-2)), so:

2(k-2)

We multiply parentheses

2k-4

Back to the equation:

-(2k-4)



We get rid of parentheses

4k-2k+4-2=0

We add all the numbers together, and all the variables

2k+2=0

We move all terms containing k to the left, all other terms to the right

2k=-2

k=-2/2

k=-1

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