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12(x)=3/2x+14
We move all terms to the left:
12(x)-(3/2x+14)=0
Domain of the equation: 2x+14)!=0We get rid of parentheses
x∈R
12x-3/2x-14=0
We multiply all the terms by the denominator
12x*2x-14*2x-3=0
Wy multiply elements
24x^2-28x-3=0
a = 24; b = -28; c = -3;
Δ = b2-4ac
Δ = -282-4·24·(-3)
Δ = 1072
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1072}=\sqrt{16*67}=\sqrt{16}*\sqrt{67}=4\sqrt{67}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-4\sqrt{67}}{2*24}=\frac{28-4\sqrt{67}}{48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+4\sqrt{67}}{2*24}=\frac{28+4\sqrt{67}}{48} $
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