6(x+4)=-2(8x-4)+8x

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Solution for 6(x+4)=-2(8x-4)+8x equation: 



6(x+4)=-2(8x-4)+8x

We move all terms to the left:

6(x+4)-(-2(8x-4)+8x)=0

We multiply parentheses

6x-(-2(8x-4)+8x)+24=0



We calculate terms in parentheses: -(-2(8x-4)+8x), so:

-2(8x-4)+8x

We add all the numbers together, and all the variables

8x-2(8x-4)

We multiply parentheses

8x-16x+8

We add all the numbers together, and all the variables

-8x+8

Back to the equation:

-(-8x+8)



We get rid of parentheses

6x+8x-8+24=0

We add all the numbers together, and all the variables

14x+16=0

We move all terms containing x to the left, all other terms to the right

14x=-16

x=-16/14

x=-1+1/7

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