12(k+1)=12(1-3k)

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Solution for 12(k+1)=12(1-3k) equation: 



12(k+1)=12(1-3k)

We move all terms to the left:

12(k+1)-(12(1-3k))=0

We add all the numbers together, and all the variables

12(k+1)-(12(-3k+1))=0

We multiply parentheses

12k-(12(-3k+1))+12=0



We calculate terms in parentheses: -(12(-3k+1)), so:

12(-3k+1)

We multiply parentheses

-36k+12

Back to the equation:

-(-36k+12)



We get rid of parentheses

12k+36k-12+12=0

We add all the numbers together, and all the variables

48k=0

k=0/48

k=0

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