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12(a-5)=3(a+2)
We move all terms to the left:
12(a-5)-(3(a+2))=0
We multiply parentheses
12a-(3(a+2))-60=0
We calculate terms in parentheses: -(3(a+2)), so:We get rid of parentheses
3(a+2)
We multiply parentheses
3a+6
Back to the equation:
-(3a+6)
12a-3a-6-60=0
We add all the numbers together, and all the variables
9a-66=0
We move all terms containing a to the left, all other terms to the right
9a=66
a=66/9
a=7+1/3
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