3(x-4)+x=2(6+3x)

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Solution for 3(x-4)+x=2(6+3x) equation: 



3(x-4)+x=2(6+3x)

We move all terms to the left:

3(x-4)+x-(2(6+3x))=0

We add all the numbers together, and all the variables

3(x-4)+x-(2(3x+6))=0

We add all the numbers together, and all the variables

x+3(x-4)-(2(3x+6))=0

We multiply parentheses

x+3x-(2(3x+6))-12=0



We calculate terms in parentheses: -(2(3x+6)), so:

2(3x+6)

We multiply parentheses

6x+12

Back to the equation:

-(6x+12)



We add all the numbers together, and all the variables

4x-(6x+12)-12=0

We get rid of parentheses

4x-6x-12-12=0

We add all the numbers together, and all the variables

-2x-24=0

We move all terms containing x to the left, all other terms to the right

-2x=24

x=24/-2

x=-12

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