12(9-7t)+9(27-4)=6(8t-9)+72

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Solution for 12(9-7t)+9(27-4)=6(8t-9)+72 equation:



12(9-7t)+9(27-4)=6(8t-9)+72
We move all terms to the left:
12(9-7t)+9(27-4)-(6(8t-9)+72)=0
We add all the numbers together, and all the variables
12(-7t+9)-(6(8t-9)+72)+923=0
We multiply parentheses
-84t-(6(8t-9)+72)+108+923=0
We calculate terms in parentheses: -(6(8t-9)+72), so:
6(8t-9)+72
We multiply parentheses
48t-54+72
We add all the numbers together, and all the variables
48t+18
Back to the equation:
-(48t+18)
We add all the numbers together, and all the variables
-84t-(48t+18)+1031=0
We get rid of parentheses
-84t-48t-18+1031=0
We add all the numbers together, and all the variables
-132t+1013=0
We move all terms containing t to the left, all other terms to the right
-132t=-1013
t=-1013/-132
t=7+89/132

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