8(x-4)-(7-3x)=3(x+3)-4(7-x)

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Solution for 8(x-4)-(7-3x)=3(x+3)-4(7-x) equation: 



8(x-4)-(7-3x)=3(x+3)-4(7-x)

We move all terms to the left:

8(x-4)-(7-3x)-(3(x+3)-4(7-x))=0

We add all the numbers together, and all the variables

8(x-4)-(-3x+7)-(3(x+3)-4(-1x+7))=0

We multiply parentheses

8x-(-3x+7)-(3(x+3)-4(-1x+7))-32=0

We get rid of parentheses

8x+3x-(3(x+3)-4(-1x+7))-7-32=0



We calculate terms in parentheses: -(3(x+3)-4(-1x+7)), so:

3(x+3)-4(-1x+7)

We multiply parentheses

3x+4x+9-28

We add all the numbers together, and all the variables

7x-19

Back to the equation:

-(7x-19)



We add all the numbers together, and all the variables

11x-(7x-19)-39=0

We get rid of parentheses

11x-7x+19-39=0

We add all the numbers together, and all the variables

4x-20=0

We move all terms containing x to the left, all other terms to the right

4x=20

x=20/4

x=5

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