12(4)+6=(10x+8)+(5x-4)

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Solution for 12(4)+6=(10x+8)+(5x-4) equation: 



12(4)+6=(10x+8)+(5x-4)

We move all terms to the left:

12(4)+6-((10x+8)+(5x-4))=0

We add all the numbers together, and all the variables

-((10x+8)+(5x-4))+130=0



We calculate terms in parentheses: -((10x+8)+(5x-4)), so:

(10x+8)+(5x-4)

We get rid of parentheses

10x+5x+8-4

We add all the numbers together, and all the variables

15x+4

Back to the equation:

-(15x+4)



We get rid of parentheses

-15x-4+130=0

We add all the numbers together, and all the variables

-15x+126=0

We move all terms containing x to the left, all other terms to the right

-15x=-126

x=-126/-15

x=8+2/5

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