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4y+2(2y+1)-(5y-1-5)=5
We move all terms to the left:
4y+2(2y+1)-(5y-1-5)-(5)=0
We add all the numbers together, and all the variables
4y+2(2y+1)-(5y-6)-5=0
We multiply parentheses
4y+4y-(5y-6)+2-5=0
We get rid of parentheses
4y+4y-5y+6+2-5=0
We add all the numbers together, and all the variables
3y+3=0
We move all terms containing y to the left, all other terms to the right
3y=-3
y=-3/3
y=-1
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