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12(3x-4)+1=5x-10+x
We move all terms to the left:
12(3x-4)+1-(5x-10+x)=0
We add all the numbers together, and all the variables
12(3x-4)-(6x-10)+1=0
We multiply parentheses
36x-(6x-10)-48+1=0
We get rid of parentheses
36x-6x+10-48+1=0
We add all the numbers together, and all the variables
30x-37=0
We move all terms containing x to the left, all other terms to the right
30x=37
x=37/30
x=1+7/30
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